(40-y)-(10y-y^2)=

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Solution for (40-y)-(10y-y^2)= equation:


Simplifying
(40 + -1y) + -1(10y + -1y2) = 0

Remove parenthesis around (40 + -1y)
40 + -1y + -1(10y + -1y2) = 0
40 + -1y + (10y * -1 + -1y2 * -1) = 0
40 + -1y + (-10y + 1y2) = 0

Combine like terms: -1y + -10y = -11y
40 + -11y + 1y2 = 0

Solving
40 + -11y + 1y2 = 0

Solving for variable 'y'.

Begin completing the square.

Move the constant term to the right:

Add '-40' to each side of the equation.
40 + -11y + -40 + y2 = 0 + -40

Reorder the terms:
40 + -40 + -11y + y2 = 0 + -40

Combine like terms: 40 + -40 = 0
0 + -11y + y2 = 0 + -40
-11y + y2 = 0 + -40

Combine like terms: 0 + -40 = -40
-11y + y2 = -40

The y term is -11y.  Take half its coefficient (-5.5).
Square it (30.25) and add it to both sides.

Add '30.25' to each side of the equation.
-11y + 30.25 + y2 = -40 + 30.25

Reorder the terms:
30.25 + -11y + y2 = -40 + 30.25

Combine like terms: -40 + 30.25 = -9.75
30.25 + -11y + y2 = -9.75

Factor a perfect square on the left side:
(y + -5.5)(y + -5.5) = -9.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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